Consider the constant function
.
Since g is constant,
.
Take any
;
a simple proof by contradiction, which follows, shows that
is an exact bound of g:
Assume there is a point
such that
.
Let
, so
:
Furthermore,
and
together imply that
.
So, for any
,
.
It follows that
is a lower and upper bound for g,
over
:
| Jeff Tupper | March 1996 |